12/(y+4)+(3/y)=(11y-4)/(y^2-16)

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Solution for 12/(y+4)+(3/y)=(11y-4)/(y^2-16) equation:


D( y )

y^2-16 = 0

y = 0

y+4 = 0

y^2-16 = 0

y^2-16 = 0

1*y^2 = 16 // : 1

y^2 = 16

y^2 = 16 // ^ 1/2

abs(y) = 4

y = 4 or y = -4

y = 0

y = 0

y+4 = 0

y+4 = 0

y+4 = 0 // - 4

y = -4

y in (-oo:-4) U (-4:0) U (0:4) U (4:+oo)

12/(y+4)+3/y = (11*y-4)/(y^2-16) // - (11*y-4)/(y^2-16)

12/(y+4)-((11*y-4)/(y^2-16))+3/y = 0

12/(y+4)+(-1*(11*y-4))/(y^2-16)+3/y = 0

(12*y*(y^2-16))/(y*(y+4)*(y^2-16))+(-1*y*(11*y-4)*(y+4))/(y*(y+4)*(y^2-16))+(3*(y+4)*(y^2-16))/(y*(y+4)*(y^2-16)) = 0

12*y*(y^2-16)-1*y*(11*y-4)*(y+4)+3*(y+4)*(y^2-16) = 0

y^3+3*y^3-40*y^2+12*y^2-176*y-48*y-192 = 0

4*y^3-28*y^2-224*y-192 = 0

4*y^3-28*y^2-224*y-192 = 0

4*(y^3-7*y^2-56*y-48) = 0

y^3-7*y^2-56*y-48 = 0

{ 1, -1, 2, -2, 3, -3, 4, -4, 6, -6, 8, -8, 12, -12, 16, -16, 24, -24, 48, -48 }

1

y = 1

y^3-7*y^2-56*y-48 = -110

1

-1

y = -1

y^3-7*y^2-56*y-48 = 0

-1

y+1

y^2-8*y-48

y^3-7*y^2-56*y-48

y+1

-y^3-y^2

-8*y^2-56*y-48

8*y^2+8*y

-48*y-48

48*y+48

0

y^2-8*y-48 = 0

DELTA = (-8)^2-(-48*1*4)

DELTA = 256

DELTA > 0

y = (256^(1/2)+8)/(1*2) or y = (8-256^(1/2))/(1*2)

y = 12 or y = -4

y in { -4, 12, -1}

4*(y+4)*(y-12)*(y+1) = 0

(4*(y+4)*(y-12)*(y+1))/(y*(y+4)*(y^2-16)) = 0

(4*(y+4)*(y-12)*(y+1))/(y*(y+4)*(y^2-16)) = 0 // * y*(y+4)*(y^2-16)

4*(y+4)*(y-12)*(y+1) = 0

( y+1 )

y+1 = 0 // - 1

y = -1

( y+4 )

y+4 = 0 // - 4

y = -4

( y-12 )

y-12 = 0 // + 12

y = 12

y in { -4}

y in { -1, 12 }

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